Question

find the value of x in;
5^(2x-1)=12^x​

Answer 1

Step-by-step explanation:

we need log of both sides

$5^(^2^x^-^1^) = 12^x\\\\5^2^x *5^-^1=12^x\\\\\frac{5^2^x}{12^x}=5\\\\(\frac{5^2}{12} )^x = 5 \\\\log((\frac{5^2}{12} ) )^x = log5\\\\x(log25-log12) = log5\\\\x=\frac{log5}{log25 - log12}$