Answer:
[tex]OH^-(aq)+H^+(aq)\rightarrow H_2O(l)[/tex]
Explanation:
Hello there!
In this case, according to the given reactants, it is firstly necessary to set up the complete molecular reaction:
[tex]NH_4OH(aq)+HClO_4(aq)\rightarrow NH_4ClO_4(aq)+H_2O(l)[/tex]
Now, by knowing that ionic species are able to ionize, we are able to write the complete ionic equation:
[tex]NH_4^++OH^-+H^++ClO_4^-\rightarrow NH_4^++ClO_4^-+H_2O(l)[/tex]
Whereas ammonium and chlorate ions are spectator ions because they remain the same on both sides of the equation. Therefore the total or net ionic equation would be:
[tex]OH^-(aq)+H^+(aq)\rightarrow H_2O(l)[/tex]
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