Question

How many grams of water can be heated from 15.0°C to 75°C using 12,500 Joules?

Answer 1

Answer:

m = 49.8 g

Explanation:

Hello there!

In this case, for this calorimetry processes we can define the involved heat in terms of mass, specific heat and temperature as shown below:

$Q=mC\Delta T$

Thus, given the heat, final and initial temperature and specific heat of water (4.184), the mass of water can be computed as shown below:

$m=\frac{Q}{C\Delta T}\\\\m=\frac{12500J}{4.184\frac{J}{g\°C}(75\°C-15.0\°C)} \\\\m=49.8g$

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