Question

What is the equation for the hyperbola shown?
X
V2
= 1
602
112
72
-
x2
112
1
602
72
x2
=
1
602
112
72
112
x2
602
1

Answer 1

Answer:

$\frac{x^{2} }{3600} - \frac{y^{2} }{121} = 1$

Step-by-step explanation:

Since the hyperbola opens left and right with a center at the origin, then

$\frac{x^{2} }{^{2} } - \frac{y^{2} }{b^{2} } = 1$

In the graph a = 60 and b = 11

So

$\frac{x^{2} }{60^{2} } - \frac{y^{2} }{11^{2} } = 1$.

$\frac{x^{2} }{3600} - \frac{y^{2} }{121} = 1$