Please help..
Solve for the area of the figure below and show work.
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Answer and Step-by-step explanation:
1. We can see that this kite-shape has 4 triangles in it.
The area of a triangle is as follows:
[tex]A = \frac{bh}{2}[/tex]
Where:
b = Base (length)
h = Height
Top Right Triangle Area:
b = 9
h = 3
A = [tex]\frac{3 * 9}{2}[/tex]
A = [tex]\frac{27}{2}[/tex]
Bottom Right Triangle Area:
b = 9
h = 3
A = [tex]\frac{3 * 9}{2}[/tex]
A = [tex]\frac{27}{2}[/tex]
Top Left Triangle Area:
b = 4
h = 3
[tex]A = \frac{4*3}{2}[/tex]
A = [tex]\frac{12}{2}[/tex]
A = 6
Bottom Left Triangle Area:
b = 4
h = 3
[tex]A = \frac{4*3}{2}[/tex]
A = [tex]\frac{12}{2}[/tex]
A = 6
Now, we add all the areas together to get the area of the kite figure.
A = [tex]\frac{27}{2}[/tex] +
A = 27 + 12
A = 39
The area of the kite figure is 39 [tex]m^{2}[/tex].
2. We have to find the area of the trapezoid.
(I'm not sure if the 9 is for the entire bottom side length)
A = [tex]\frac{a + b}{2} h[/tex]
to find the area of the entire trapezoid.
A = [tex]\frac{2.4 + 9}{9}[/tex] × 8.2
A ≈ 46.74 [tex]mi^{2}[/tex]
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