Question

Mhanifa can you please help? I will mark brainliest!

Answer 1

Answer:

Property of kite used to solve this

• Diagonals are perpendicular
• One diagonal is an angle bisector (WY)

(20)

• ∠XYZ is double the ∠XYV
• ∠XYV is complementary with ∠VXY
• m∠XYZ = 2(90° - 58°) = 64°

(21)

• ∠VZW is complementary with ∠VWZ and ∠VWZ is half of ∠ZWX
• m∠VZW = 90° - 50°/2 = 65°

(22)

• ∠ZWV is half of ∠ZWX
• m∠ZWV = 1/2*50° = 25°

(23)

• m∠WZY = m∠VZW + m∠VZY = m∠VZW + m∠VXY
• m∠WZY = 65° + 58° = 123°