Question

The ferris wheel has a radius of 68 feet.
The clearance between the wheel and the ground is 14 feet.
The rectangular coordinate system shown has its origin on the ground directly below the center of the wheel.
Use the coordinate system to write the equation of the circular wheel?

Coordinates of center (0,82)

Answer 1

here are the complete steps to get your equation
Coordinates of center (0,82)
radius 68
feet equation is
(x-0)^2+(y-82)^2=68^2

Answer 2

Answer: $(x)^2+(y-82)^2=(68)^2$

Step-by-step explanation:

Given : The Ferris wheel has a radius of 68 feet.

The clearance between the wheel and the ground is 14 feet.

Also, the rectangular coordinate system shown has its origin on the ground directly below the center of the wheel.

So the x coordinate of center of wheel must  be 0 , and y coordinate = 68+14=82

Thus, Coordinates of center =(0,82)

The equation of circle is given by :-

$(x-h)^2+(y-k)^2=r^2$

Put center (h,k)=(0,82) and r= 68 , we get

$(x)^2+(y-82)^2=(68)^2$

Hence, the equation of the circular wheel is

$(x)^2+(y-82)^2=(68)^2$