Respuesta :
The lewis structure looks something like this:
O=C-O ....| ...O
with the hydrogen atoms bonded to two of the Oxygen atoms. There are two other resonance structures which means that a double bond does not actual exist in the molecule. Instead there's a pair of delocalized electrons that span the entire molecule. This means that all three bonds are actually equal and thus the molecule has a trigonal planar geometry. You can also tell that it's trigonal planar because the central atom is sp2 hybridized.
O=C-O ....| ...O
with the hydrogen atoms bonded to two of the Oxygen atoms. There are two other resonance structures which means that a double bond does not actual exist in the molecule. Instead there's a pair of delocalized electrons that span the entire molecule. This means that all three bonds are actually equal and thus the molecule has a trigonal planar geometry. You can also tell that it's trigonal planar because the central atom is sp2 hybridized.
Answer : The shape of [tex]H_2CO_3[/tex] is, trigonal planar.
Explanation :
Lewis-dot structure : It shows the bonding between the atoms of a molecule.
When we are determining the shape of a molecule then it is important to draw a Lewis-dot structure and for drawing a Lewis-dot structure we should know that how many total number of valance electrons present in a given compound or a molecule.
The given molecule is, [tex]H_2CO_3[/tex]
As we know that hydrogen has '1' valence electrons, carbon has '4' valance electrons and oxygen has '6' valence electron.
Therefore, the total number of valence electrons in [tex]H_2CO_3[/tex] = 2 + 4 + 18 = 24
Now we have to determine the hybridization of carbon in [tex]H_2CO_3[/tex]
Number of bond pairs = 3
Number of lone pairs = 0
Number of atomic orbitals around carbon atom = 3 + 0 = 3
So, hybridization will be [tex]sp^2[/tex] and the shape is, trigonal planar.
The Lewis-dot structure is shown below.
