Answer: The specific heat of the metal is [tex]0.23J/g^0C[/tex]
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
[tex]Q=m\times c\times \Delta T[/tex]
Q = Heat absorbed=[tex]2.50kJ=2500J[/tex]
m= mass of substance = 135 g
c = specific heat capacity = ?
Initial temperature = [tex]T_i[/tex] = 19.5°C
Final temperature = [tex]T_f[/tex] =100.0°C
Change in temperature ,[tex]\Delta T=T_f-T_i=(100-19.5)^0C=80.5^0C[/tex]
Putting in the values, we get:
[tex]2500=135\times c\times 80.5^0C[/tex]
[tex]c=0.23J/g^0C[/tex]
The specific heat of the metal is [tex]0.23J/g^0C[/tex]
