Question

What are the coordinates of the vertex of the graph of the function y = –x² + 6x –11?

(3, –2)
(3, 16)
(–3, –29)
(–3, –20)

Answer 1

The answer is (3,-2) Use x=-b/2a to get the x value then substitute that number back into the equation to get y. x=-6/-2 = 3 -(3)^2+6(3)-11 =-2

Answer 2

Answer:

A. $(3,-2)$

Step-by-step explanation:

We have been given a function formula $y=-x^2+6x-11$. We are asked to find the coordinates of the vertex of the graph.

We know that the x-coordinate of an equation in form $y=ax^2+bx+c$ can be determined using formula $\frac{-b}{2a}$.

We can see that value of b is 6 and value of a is -1.

$\frac{-6}{2(-1)}$

$\frac{-6}{-2}$

$3$

Now, we will substitute $x=3$ in given formula to find y-coordinate.

$y=-(3)^2+6(3)-11$

$y=-9+18-11$

$y=-2$

Therefore, the coordinates of vertex of the given function are $(3,-2)$.