Question

High-pressure liquid chromatography (HPLC) is a method used in chemistry and biochemistry to purify chemical substances. The pressures used in this procedure range from around 500 kilopascals (500,000 Pa) to about 60,000kPa (60,000,000Pa ). It is often convenient to know the pressure in torr. If an HPLC procedure is running at a pressure of 5.10×10^8 , what is its running pressure in torr?

Answer 1

its running pressure in torr would be :

5.10 x 10^8 pa  x 1kPa/1000 Pa x 760 / 101.325 kPa

= 5.10 x 10 ^5  x   76 x 10^-1  x 1.01325 x 10 ^-2

= 392.7375 x 10^2

= 3.927275 x 10^4

ope this helps

Answer 2

Answer:

$3.83x10^6torr$

Explanation:

Hello,

In this case, to perform the following unit conversion, it is convenient to know that 1 atm equals 101,325 Pa and 1 atm equals 760 torr:

$5.10x10^8Pa*\frac{1atm}{101325Pa}*\frac{760torr}{1atm}=3.83x10^6torr$

Best regards.