Respuesta :
- subtract 3rd from second
2x +3y -3z = -6
2x +2y -z = 0
---------------
0 y -2z = -6
- multiply first by -2 and assum by second
-2x -2y +8z = 14
2x +3y -3z = -6
----------------
0 y +5z = 8
y-2z=-6
y+5z=8
---------- subtract second from first
0 -7z =-14
z=2
y+5z=8
y+5*2=8
y+10=8
y=-2
z=2
y=-2
x+y -4z=-7
x +(-2) -4(2) = -7
x-2-8=-7 x-10=-7
x=3
x=3
y=-2
z=2
2x +3y -3z = -6
2x +2y -z = 0
---------------
0 y -2z = -6
- multiply first by -2 and assum by second
-2x -2y +8z = 14
2x +3y -3z = -6
----------------
0 y +5z = 8
y-2z=-6
y+5z=8
---------- subtract second from first
0 -7z =-14
z=2
y+5z=8
y+5*2=8
y+10=8
y=-2
z=2
y=-2
x+y -4z=-7
x +(-2) -4(2) = -7
x-2-8=-7 x-10=-7
x=3
x=3
y=-2
z=2
Answer:
Step-by-step explanation:
- subtract 3rd from second
2x +3y -3z = -6
2x +2y -z = 0
---------------
0 y -2z = -6
- multiply first by -2 and assum by second
-2x -2y +8z = 14
2x +3y -3z = -6
----------------
0 y +5z = 8
y-2z=-6
y+5z=8
---------- subtract second from first
0 -7z =-14
z=2
y+5z=8
y+5*2=8
y+10=8
y=-2
z=2
y=-2
x+y -4z=-7
x +(-2) -4(2) = -7
x-2-8=-7
x-10=-7
x=3
x=3
y=-2
z=2