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In ΔCDE, the measure of ∠E=90°, the measure of ∠C=43°, and CD = 95 feet. Find the length of EC to the nearest tenth of a foot.

In ΔCDE the measure of E90 the measure of C43 and CD 95 feet Find the length of EC to the nearest tenth of a foot class=

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sqdancefan

9514 1404 393

Answer:

  69.5

Step-by-step explanation:

The useful trig relation in this case is ...

  Cos = Adjacent/Hypotenuse

  cos(43°) = x/95

  x = 95×cos(43°) ≈ 69.5 . . . . feet
69.5 is the answer I’m sure

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