Graph y ≤ (x + 2)^2.
Click on the graph until the correct graph appears.
![Graph y x 22 Click on the graph until the correct graph appears class=](https://us-static.z-dn.net/files/d6d/9a26375c08f2dd47dba8f62b3fb70773.gif)
![Graph y x 22 Click on the graph until the correct graph appears class=](https://us-static.z-dn.net/files/d91/f78915bbd31db17ffc9d3038d0eee886.gif)
![Graph y x 22 Click on the graph until the correct graph appears class=](https://us-static.z-dn.net/files/dc8/216cfa54370f58c99170b1fbdd7b4ac3.gif)
![Graph y x 22 Click on the graph until the correct graph appears class=](https://us-static.z-dn.net/files/d6f/97d6a9bfbbfd5f1aedbec481114e7a11.gif)
Answer:
the first one is the correct one
Step-by-step explanation:
a great way to check this is to use demos .com
Answer:
its the first one
Step-by-step explanation:
our vertex is (-2,0)
so replace it in the equation y ≤ (x + 2)^2
so, 0 ≤ (-2 + 2)^2
= 0 ≤ (-4)^2
= 0 ≤ 16
look at that statement, is 0 less than or equal to 16? Yes. Therefore it is correct, so you shade out side of the parabola.
TIP: If the parabola opens up and:
y <, then shade outside.
y >, then shade inside.
Do the opposite if the parabola opens down.