Find the value of x. Round to the nearest tenth (one decimal place)
19
21
![Find the value of x Round to the nearest tenth one decimal place 19 21 class=](https://us-static.z-dn.net/files/df1/1e6f7b1aee86d141f45adc1ffc9b25ab.png)
Using the Pythagorean theorem:
X = sqrt(21^2 - 19^2)
X = sqrt(441 - 361)
X = sqrt(80)
X = 8.944
Rounded to the nearest tenth = 8.9
Answer:
x = ~8.9
Step-by-step explanation:
a^2 + b^2 = c^2
c is the long side
a and b are the other two shorter sides
this means
x^2 + 19^2 = 21^2
x^2 + 361 = 441
x^2 = 441- 361
x^2 = 441- 361
x^2 = 80
square root of 80 = ~8.9
x = ~8.9