Question

A company manufactures computers. Function N represents the number of components that a new employee can assemble per day. Function E represents the number of components that an experienced employee can assemble per day. In both functions, t represents the number of hours worked in one day.
N(t)=50t/t+4
E(t)= 70t/t+3

Which function describes the difference of the number of components assembled per day by the experienced and new employees?
A. D(t)= 10t(2t+13)/t+3
B. D(t)= 10t(2t+13)/ (t+4)(t+3)
C. D(t)= 10t(2t-13)/t+4
D. D(t)=10t(2t-13)/ (t+4)(t+3)

Answer 1

The difference of the number of components assembled per day by the experienced and new Employees is : D(t)= 10t(2t+13)/ (t+4)(t+3)

Here we perform subtraction :

D(t) = N(t) - E(t)

N(t) = 50t / (t+4)

E(t) = 70t / (t+3)

The difference :

D(t) = E(t) - N(t)

D(t) = [70t / (t+3)] - [50t / (t+4)]

The L.C.M of (t+3) and (t+4) is (t+3)(t+4)

[70t(t+4)] - [50t(t+3)] / (t+3)(t+4)

70t² + 280t - [50t² + 150t] / (t+3)(t+4)

[70t² + 280t - 50t² - 150t] / (t+3)(t+4)

20t² + 130t / (t+3)(t+4)

D(t) = 10t(2t + 13) / (t+3)(t+4)

The difference of the number of components assembled is : D(t)= 10t(2t+13)/ (t+4)(t+3)

Learn more : https://brainly.com/question/1166214

Answer 2

Answer:b

Step-by-step explanation:

plato