Answer:
0.014 Liters needed
Explanation:
Given 5.128 grams NaCl + ?Water Solvent => 6.3M solution
Solution Concentration = moles solute/liter solution = Molarity (M)
=> Molarity (M) = 6.3M = (5.128g NaCl/58g·mole⁻¹) / Volume of Sol'n (L)
∴ Vol of Solution = Vol of Water Solvent needed
= (5.128g NaCl/58g·mole⁻¹) / 6.3M
= 0.0884 mole NaCl / 6.3 mol/L = 0.014 Liters water solvent.
Method of Mixing:
Transfer 5.128g NaCl into mixing container and add solvent water up to but not to exceed 0.014 Liters (=14 ml) total volume. Mix till homogeneous.
