Question

how many moles of ag can be produced if 250g of CU are reacted with excess agNo3, according to the equation Cu(s) + 2AgNO3(aq) -> 2Ag(s) + Cu(NO3)2(aq)?

Answer 1

Answer:

$250 \times \frac{1}{63.5} \times \frac{2}{1} = 7.874mol \: ag$