Question

Given: Circle O with diameter LN and inscribed angle LMN
Prove: Angle L M N is a right angle.

Circle O is shown. Line segment L N is a diameter. Points L, M, N, and K are on the circle. Lines connect each point.

What is the missing reason in step 5?


Statements

Reasons
1. circle O has diameter LN and inscribed angle LMN 1. given
2. Arc L K N is a semicircle 2. diameter Circle divides into 2 semicircles
3. circle O measures 360o 3.
measure of a circle is 360o

4. m Arc L K N = 180o 4. definition of semicircle
5. m∠LMN = 90o 5. ?
6. ∠LMN is a right angle 6. definition of right angle
HL theorem
inscribed angle theorem
diagonals of a rhombus are perpendicular.
formed by a tangent and a chord is half the measure of the intercepted arc.

Answer 1

Answer:

B : inscribed angle theorem

Step-by-step explanation:

Answer 2

The missing reason in step 5 is; Inscribed angle theorem.

Inscribed angle theorem

Within the context of circle geometry, an inscribed angle is the angle formed in the interior of a circle as a result of the intersection of two chords on the circumference of the circle.

Put differently, an inscribed angle is defined by two chords of the circle sharing an endpoint.

Ultimately, since the chords LM and MN intersect on the circumference, with LM being the diameter of the circle, then the measure of angle LMN is 90°.

Read more on inscribed angle theorem;

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