Question

2. What is the pressure of a fixed volume of hydrogen gas at 30.0°C if it has a pressure of 1.11 atm at 15.0°C?

Answer 1

Answer:

1.17

Explanation:

1.17 hope this helps

Answer 2

The initial pressure of the fixed volume of the hydrogen gas as the pressure and temperature decreased is 1.17atm.

What is Gay-Lussac's law?

Gay-Lussac's law states that the pressure exerted by a given quantity of gas varies directly with the absolute temperature of the gas.

It is expressed as;

P₁/T₁ = P₂/T₂

Given the data in the question;

• Initial pressure P₁ = ?

• Initial temperature T₁ = 30.0°C = 303.15K

• Final pressure P₂ = 1.11atm

• Initial temperature T₂ = 15.0°C = 288.15K

We substitute our values into the expression above.

P₁/T₁ = P₂/T₂

P₁T₂ = P₂T₁

P₁ = P₂T₁ / T₂

P₁ = ( 1.11atm × 303.15K ) / 288.15K

P₁ = 336.4965 / 288.15K

P₁ = 1.17atm

Therefore, the initial pressure of the fixed volume of the hydrogen gas as the pressure and temperature decreased is 1.17atm.

Learn more about Gay-Lussac's law here: https://brainly.com/question/1358307

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