Answer:
EF = 13 units
Step-by-step explanation:
Points E and F are the ends of segment EF.
Coordinates of E → (-7, -5)
Coordinates of F → (-2, 7)
Since, length of a segment joining points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by,
Length of segment = [tex]\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}[/tex]
Length of segment EF = [tex]\sqrt{(-7+2)^2+(-5-7)^2}[/tex]
= [tex]\sqrt{(-5)^2+(-12)^2}[/tex]
= [tex]\sqrt{169}[/tex]
= 13
Therefore, length of segment EF is 13 units.
Answer:
13 units.
The answer above is correct!
Step-by-step explanation:
