Answer:
Step-by-step explanation:
3x²+10x>8
[tex]x^{2} +\frac{10}{3} x+(\frac{5}{3} )^2>\frac{8}{3}+(\frac{5}{3} )^2\\(x+\frac{5}{3} )^2>\frac{8}{3}+\frac{25}{9} \\(x+\frac{5}{3})^2>\frac{49}{9}\\|x+\frac{5}{3}|>\frac{7 }{3} \\x+\frac{5}{3}>\frac{7}{3} \\or\\x>\frac{-5+7 }{3} \\or\\x>\frac{2}{3}\\\\and\\x+\frac{5}{3}<-\frac{-7 }{3} \\or\\x<\frac{-5-7 }{3}\\x<-4[/tex]
