Question

please help me its hard!

Answer 1

Answer:

600

Step-by-step explanation:

Consider ABC and ACD as two triangles. And AC as a base to both of them

so,

AC = AO + OC

= 15 + 25

= 40

Now the area of ABC =

$\frac{1}{2}\times AC\times OB\\= \frac{1}{2}\times 40 \times 10\\= 200$

In the same way, the area of ACD =

$\frac{1}{2}\times AC\times OD\\= \frac{1}{2}\times 40 \times 20\\= 400$

Both added together 400 + 200 = 600