Question

2y^2-4y-8=-y+y help I don't get it :( quadratic equation

Answer 1

2y²-4y-8=-y+y
2y²-4y-8=0
Divide all be its common factor 2
(2y²-4y-8=0)/2
y²-2y-4=0
The quadratic eq. would be y²-2y-4=0