what is the value of x

Perpendicular = x
Hypotenuese = 30
[tex]{ \sf{sin \: \: 45 {}^{ \degree} = \dfrac{1}{ \sqrt{2} } = \dfrac{x}{ 30} }}[/tex]
[tex]{ \sf{x = \dfrac{30}{ \sqrt{2} } }}[/tex]
Answer:
15√2 is your answer
Step-by-step explanation:
for your question
relation between perpendicular and hypotenuse is given by sin angle
sin45=p/h
sin45=x/30
x=sin45×30=15√2