Respuesta :
Answer: C2H5F
Explanation:
Take each percentage of the element and divide it by that element's mass. (This is the biggest number for the element found at the bottom of its cell on the periodic table.) Round up or down to whole numbers, and then divide each answer by the lowest answer you got from doing this.
So, Carbon: (49.97/12.01)= 4.
Hydrogen: (10.51/1.01)= 10.
Fluorine: (39.52/19)=2. Fluorine has the lowest answer, therefore we will go:
4/2= 2.
10/2=5
2/2=1.
There you have your answer! C2H5F
[tex]C_2H_5F[/tex] is the empirical formula for ethyl fluoride if the compound contains 49.97% carbon, 10.51% hydrogen, and 39.52% fluorine by mass.
What is an empirical formula?
The empirical formula is the chemical formula of a compound that gives the proportions (ratios) of the elements present in the compound but not the actual numbers or arrangement of atoms.
Take each percentage of the element and divide it by that element's mass. (This is the biggest number for the element found at the bottom of its cell on the periodic table.)
Round up or down to whole numbers, and then divide each answer by the lowest answer you got from doing this.
So, Carbon: (49.97 ÷ 12.01)= 4.
Hydrogen: (10.51 ÷ 1.01)= 10.
Fluorine: (39.52 ÷ 19)=2. Fluorine has the lowest answer, therefore we will go:
4 ÷ 2= 2.
10 ÷ 2=5
2 ÷ 2=1.
Hence, [tex]C_2H_5F[/tex] is the empirical formula for ethyl fluoride if the compound contains 49.97% carbon, 10.51% hydrogen, and 39.52% fluorine by mass
Learn more about the empirical formula here:
brainly.com/question/14044066
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