Question

A hemispherical tank is filled with water and has a diameter of 22 feet. If water
weighs 62.4 pounds per cubic foot, what is the total weight of the water in a full tank,
to the nearest pound?

Answer 1

Answer:

just do the exam

Step-by-step explanation:

Answer 2

Answer:

173,949 lb

Step-by-step explanation:

Volume of a sphere:

$V_{sphere} = \dfrac{4}{3}\pi r^3$

A hemisphere is half of a sphere, so its volume is half of the volume of a sphere with the same diameter. Also, radius = diameter/2.

$V_{hemisphere} = \dfrac{2}{3}\pi (\dfrac{d}{2})^3$

$V_{hemisphere} = \dfrac{2}{3} \times 3.14159 \times (\dfrac{22~ft}{2})^3$

$V_{hemisphere} = 2787.639~ft^3$

Now we use the density of water to find the weight of the water contained in the tank.

weight = volume * density

weight = 2787.639 ft^3 * 62.4 lb/ft^3

weight = 173,949 lb