Question

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Be
DE
be
BE
BBEE
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BbEE
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Two fruit flies that are heterozygous for body color
and eye color are crossed. Brown body color is
dominant to black body color. Red eye color is
dominant to brown eye color.
Use the Punnett square to determine the ratio of
offspring with the described trait to the total
number of offspring:
Brown body and red eyes | I
Brown body and brown eyes
Black body and red eyes
Black body and brown eyes
Be
ВВЕe
BBee
BbEe
Bbee
DE
BbEE
BbEe
bbEE
bbEe
DONE
be
BbEe
Bbee
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bbee

Answer 1

Answer:

9 and 16 for the first row of boxes

3 and 16 for the second row

3 and 16 for the third row

1 and 16 for the last row

Explanation:

I did it on edge

Answer 2

The ratio of offspring with the described traits to the total number of offspring would be 9/16, 3/16, 3/16, and 1/16 respectively.

What are dihybrid crosses?

They are crosses involving two traits. when the traits are independent, the phenotypic ratio of the resulting offspring follows the ratio established by Mendel.

In this case, the two traits follow the Mendelian pattern and thus, assort independently.

Hence, the traits and their respective ratios would be:

Brown body, Red eyes - 9/16

Brown body, brown eyes - 3/16

Black body, red eyes - 3/16

Brown body, brown eyes - 1/16

More on dihybrid crosses can be found here: https://brainly.com/question/1185199