how do I write the equation of the parabola in intercept form

Answer:
The equation of the parabola in intercept form is [tex]y = -\frac{3}{4}\cdot x\cdot (x-4)[/tex].
Step-by-step explanation:
The equation of the parabola in intercept form is defined by following formula:
[tex]y = a\cdot (x-r_{1})\cdot (x-r_{2})[/tex] (1)
Where:
[tex]x[/tex] - Independent variable.
[tex]y[/tex] - Dependent variable.
[tex]a[/tex] - Vertex constant.
[tex]r_{1}, r_{2}[/tex] - Intercepts of the parabola.
According to the graph, we find that intercepts are 0 and 4, respectively, and a point in the parabola is [tex](x,y) = (3, 2.25)[/tex]. If we know that [tex]r_{1} = 0[/tex], [tex]r_{2} = 4[/tex] and [tex](x,y) = (3, 2.25)[/tex], then the vertex constant is:
[tex]a = \frac{y}{(x-r_{1})\cdot (x-r_{2})}[/tex]
[tex]a = -\frac{3}{4}[/tex]
The equation of the parabola in intercept form is [tex]y = -\frac{3}{4}\cdot x\cdot (x-4)[/tex].