Answer:
The slope of the line that contains FG is -1
Step-by-step explanation:
Given
[tex]x -y= 2[/tex] --- equation of EF
Required
Determine the equation of FG
First, we calculate the slope of EF
[tex]x -y= 2[/tex]
Make y the subject
[tex]y = x - 2[/tex]
A linear equation has the form:
[tex]y = mx + b[/tex]
Where
[tex]m = slope[/tex]
By comparison:
[tex]m = 1[/tex]
In square EFGH, EF and FG are perpendicular.
So, the relationship between their slopes is:
[tex]m_2 = -\frac{1}{m_1}[/tex]
Where
[tex]m_1 = m = 1[/tex] --- slope of EF
The equation becomes:
[tex]m_2 = -\frac{1}{1}[/tex]
[tex]m_2 =-1[/tex]
