Answer:
277.0g of CO₂ is theoretical yield
Explanation:
In the reaction, 2 moles of C₄H₁₀ react with 8 moles of CO₂.
To solve this question, we must convert the volume of the C₄H₁₀to moles. Then, using the chemical reaction, find the moles of CO₂ produced and its mass as follows:
PV = nRT
Assuming STP conditions:
P = 1atm
V = 35.5L
n are moles
R = 0.082atmL/molK
T = 273.15K
Replacing:
n = PV/RT
n = 1atm*35.25L / 0.082atmL/molK*273.15K
n = 1.574 moles C₄H₁₀
Assuming all these moles are converted in CO₂ (theoretical yield), the moles of carbon dioxide are:
1.574 moles C₄H₁₀ * (8mol CO₂ / 2mol C₄H₁₀) = 6.295 moles CO₂
And the theoretical yield in mass is:
6.295 moles CO₂ * (44.01g / mol) =
