Question

Identify the 31st term of an arithmetic sequence where a1 = 26 and a22 = −226.

−334
−274
−284
−346

Answer 1

Answer:

a31 = -334

Step-by-step explanation:

Given:

a1 = 26

a22 = -226

Find:

a31

Computation:

a22 = a + 21d

-226 = 26 + 21d

d = -12

a31 = a + 30d

a31 = 26 + 30(-12)

a31 = 26 - 360

a31 = -334

Answer 2

a1 = 26 and a22 = −226.

Answer:

A)  −334