Answer:
The answer is "3.57 and 0.07".
Explanation:
Using the slop formula:
[tex]=\frac{n_2-n_1}{n_2-n_1}\\\\ =\frac{0.714-0.357}{0.20-0.10} \\\\ = ABSORPTIVITY, \ \ a=3.57 \\\\A= a\times b \times c[/tex]
Given:
[tex]A=0.250[/tex]
length path [tex]b=1[/tex]
from calibration it is found that
[tex]a=3.57\\\\consentation \ c=\frac{A}{a\times b} \\\\C=\frac{0.250}{3.57\times 1}[/tex]
[tex]=0.07 \ M[/tex]