Question

Which equation of a line passes through the points (-1,3) and (2,-3)?​

Answer 1

Answer:

y=-2x+1

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-3-3)/(2-(-1))

m=-6/(2+1)

m=-6/3

m=-2

y-y1=m(x-x1)

y-3=-2(x-(-1))

y-3=-2(x+1)

y=-2x-2+3

y=-2x+1