Determine which cross products are proportionate to each other. Select all situations that apply.

1/2 = 2/24
3/8y = 9/24y
4 = 64/16
x/y = y/x
3z/x = 9z/3x

Respuesta :

3/8y = 9/24 since 3*3=9 and 8*3=24
4 = 64/16 since 16*4=64
3z/x = 9z/3x since 3z*3=9z and x*3=3x

Answer:

Part 1) [tex]\frac{1}{2} =\frac{2}{24}[/tex]

[tex]\frac{2}{24}[/tex] is [tex]\frac{1}{12}[/tex] in reduced form .

[tex]\frac{1}{2} =\frac{2}{24}[/tex]

[tex]\frac{1}{2}\neq\frac{1}{12}[/tex]

These are not proportionate to each other

Part 2) [tex]\frac{3}{8}y =\frac{9}{24}y[/tex]

[tex]\frac{9}{24}y[/tex] is [tex]\frac{3}{8}y[/tex] in reduced form .

So,  [tex]\frac{3}{8}y =\frac{9}{24}y[/tex]

So, these are proportionate to each other .

Part 3) [tex]4 =\frac{64}{16}[/tex]

[tex]\frac{64}{16}[/tex] is [tex]\frac{4}{1}[/tex] in reduced form .

So,  [tex]4 =\frac{64}{16}[/tex]

So, these are proportionate to each other .

Part 4) [tex]\frac{x}{y} =\frac{y}{x}[/tex]

Since we cannot reduce [tex]\frac{x}{y}[/tex] into [tex]\frac{y}{x}[/tex] and vice versa.

So, These are not proportionate to each other

Part 5) [tex]\frac{3z}{x} =\frac{9z}{3x}[/tex]

[tex]\frac{9z}{3x}[/tex] is [tex]\frac{3z}{x}[/tex] in reduced form .

So, [tex]\frac{3z}{x} =\frac{9z}{3x}[/tex]

So, these are proportionate to each other .