Question

In a class of 30 students 16 have a cat and 15 have a dog there are 11 students who have a cat and a dog what is the probability that a student has a dog given they do not have a cat?

Answer 1

so we know 11 have cats and dogs and 15 have dogs so do 15-11=4 and divide that by all the students which is 30 and get 13.3%

Answer 2

The probability that a student has a dog given they do not have a cat is 0.1333.

What is probability?

Probability deals with the occurrence of a random event. The chance that a given event will occur. It is the measure of the likelihood of an event to occur.The value is expressed from zero to one.

For the given situation,

Total number of students = 30

$n(s)=30$

Number of students have cat = 16

Number of students have dog = 15

Number of students have a cat and a dog = 11

The event is the probability that a student has a dog given they do not have a cat,

$n(e)=15-11$

⇒ $4$

Thus the probability that a student has a dog given they do not have a cat is

⇒ $P(e)=\frac{n(e)}{n(s)}$

⇒ $P(e)=\frac{4}{30}$

⇒ $P(e)=0.1333$

Hence we can conclude that the probability that a student has a dog given they do not have a cat is 0.1333.

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