Given:
The equation is
[tex]\left(z+\dfrac{6}{7}\right)+\dfrac{2}{14}=-1[/tex]
To find:
The solution of the given equation.
Solution:
We have,
[tex]\left(z+\dfrac{6}{7}\right)+\dfrac{2}{14}=-1[/tex]
It can be written as
[tex]\left(z+\dfrac{6}{7}\right)+\dfrac{1}{7}=-1[/tex]
[tex]\left(z+\dfrac{6}{7}\right)=-1-\dfrac{1}{7}[/tex]
Multiply both sides by 7.
[tex]7z+6=-7-1[/tex]
[tex]7z+6=-8[/tex]
[tex]7z=-8-6[/tex]
[tex]7z=-14[/tex]
Divide both sides by 7.
[tex]z=\dfrac{-14}{7}[/tex]
[tex]z=-2[/tex]
Therefore, the value of z is -2.
