From the indicated equation Zn +2 HCl → ZnCl2 + H2 if 7.56 moles of HCl are used with Zn, how many
moles of the product H2 ZnCl2 would be formed?
A) 15.12 mol
B) 5.20 mol
C) 58 mol
D) 3.78 mol
D. The molar ratio for the reactant HCl and both products ZnCl2 and H2 are 2:1. Therefore, for every 2 moles of reactants, you’ll get 1 mole of product. 7.56 moles HCl will generate 3.78 moles of products
