Answer:
[tex]x^2 + 2xy + y^2[/tex]
Step-by-step explanation:
[tex](x+y)^2 = (x+y)(x+y)[/tex]
F.O.I.L. the equation (first, outer, inner, last)
[tex](x+y)(x+y) = (x*x) + (x*y) + (x*y) + (y*y)[/tex]
[tex](x*x) + (x*y) + (x*y) + (y*y) = x^2 + xy +xy+y^2 = x^2 +2xy+y^2[/tex]
