Answer:
log 7
Step-by-step explanation:
Using the rules of logarithms
log x + log y ⇔ log (xy )
log x - log y ⇔ log ([tex]\frac{x}{y}[/tex] )
Given
log[tex]\frac{14}{3}[/tex] + log[tex]\frac{11}{5}[/tex] - log[tex]\frac{22}{15}[/tex]
= log ([tex]\frac{14}{3}[/tex] × [tex]\frac{11}{5}[/tex] ) - log[tex]\frac{22}{15}[/tex]
= log ([tex]\frac{154}{15}[/tex] ) - log[tex]\frac{22}{15}[/tex]
= log ( [tex]\frac{154}{15}[/tex] ÷ [tex]\frac{22}{15}[/tex] )
= log ([tex]\frac{154}{15}[/tex] × [tex]\frac{15}{22}[/tex] )
= log[tex]\frac{154}{22}[/tex]
= log 7
