Question

a shark is located 45 feet directly below a swimmer on the surface of the water. the angle of depression from a boat nearby to the shark is 64 degrees. how far is the swimmer from the boat​

Answer 1

Using the slope concept, it is found that the swimmer is 21.95 feet from the boat.

What is a slope?

• The slope is given by the vertical change divided by the horizontal change.

• It's also the tangent of the angle of depression.

In this problem:

• A shark is located 45 feet directly below a swimmer on the surface of the water, hence the vertical change is 45.

• The distance d is the horizontal change, which we want to find.

• The angle is of 64º.

Hence:

$\tan{64^{\circ}} = \frac{45}{d}$

$d = \frac{45}{\tan{64^{\circ}}}$

$d = 21.95$

The swimmer is 21.95 feet from the boat.

You can learn more about the slope concept at https://brainly.com/question/26342863