a shark is located 45 feet directly below a swimmer on the surface of the water. the angle of depression from a boat nearby to the shark is 64 degrees. how far is the swimmer from the boat​

Respuesta :

Using the slope concept, it is found that the swimmer is 21.95 feet from the boat.

What is a slope?

  • The slope is given by the vertical change divided by the horizontal change.
  • It's also the tangent of the angle of depression.

In this problem:

  • A shark is located 45 feet directly below a swimmer on the surface of the water, hence the vertical change is 45.
  • The distance d is the horizontal change, which we want to find.
  • The angle is of 64º.

Hence:

[tex]\tan{64^{\circ}} = \frac{45}{d}[/tex]

[tex]d = \frac{45}{\tan{64^{\circ}}}[/tex]

[tex]d = 21.95[/tex]

The swimmer is 21.95 feet from the boat.

You can learn more about the slope concept at https://brainly.com/question/26342863

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