Question

17.5 mL of 0.1000M NaOH was required to neutralize 25.0 mL of HCl. What was the molarity of the HCl?

Answer 1

Answer: The molarity of $HCl$ is 0.07 M

Explanation:

According to the neutralization law,

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1$ = basicity $HCl$ = 1

$M_1$ = molarity of $HCl$ solution = ?

$V_1$ = volume of  $HCl$ solution = 25.0 ml

$n_2$ = acidity of $NaOH$ = 1

$M_1$ = molarity of $NaOH$ solution = 0.1000 M

$V_1$ = volume of  $NaOH$ solution = 17.5 ml

Putting in the values we get:

$1\times M_1\times 25.0=1\times 0.1000\times 17.5$

$M_1=0.07M$

Therefore, molarity of $HCl$ is 0.07 M