Respuesta :
Answer:
Number of marbles with Williams at the starting = 192
Step-by-step explanation:
Let total number of marbles with Williams = m
He lost marbles = 25% of the total number
= [tex]\frac{25}{100}\times m[/tex]
= [tex]\frac{m}{4}[/tex]
Remaining marbles with Williams = m - [tex]\frac{m}{4}[/tex]
= [tex]\frac{3m}{4}[/tex]
He gave marbles to his brother = [tex]\frac{1}{6}[/tex]th of the remaining marbles
= [tex]\frac{1}{6}\times \frac{3m}{4}[/tex]
= [tex]\frac{m}{8}[/tex]
Remaining marbles after giving marbles to his brother = 120
Therefore, [tex]\frac{3m}{4}-\frac{m}{8}=120[/tex]
[tex]\frac{6m}{8}-\frac{m}{8}=120[/tex]
[tex]\frac{5m}{8}=120[/tex]
m = [tex]\frac{120\times 8}{5}[/tex]
m = 192
Number of marbles with Williams at the starting = 192
