Answer:
1.) ((a+1)^3)+(x^3) = a^3 + 3a^2 + 3a + x^3 + 1
2.) ((y-2)^3)-27 = (y^2-y + 7) x ( y - 5 )
3.) ((a-b)^3)+b^3 = a (a^2 - 3ab + 3b^2 )
4.) (8x^3)+((x-y)^3) = 9x^3 -3x^2 y + 3xy^2 - y^3
5.) (27a^3)-((a-b)^3) = 26a^3 + 3a^2 b - 3ab^2 + b^3
5) factor = (a+b)(a+b)^ 2 if a is squared and if b is cubed and moved over to = 0 then we can find (a+b)(a+b)^2 but in all cases of quadratics you can set (x -1 ) = 1 and (x-1 ) = 1 so they are always positive. Which is the same if they start of negative.
For question 5 we have a factor solved (a+b)(a+b)^ 2
Which means the same as this expansion
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