Answer:
a = 0, b = -15
Step-by-step explanation:
Given the following complex number;
x1 = 3(cosπ+isinπ)
x2 = 5(cosπ/2 - isinπ/2)
x1x2 = 15(cosπcosπ/2 - icosπsinπ/2+isinπcosπ/2 -i²sinπsinπ/2)
x1x2 = 15(0 - i(-1)+0 -0)
x1x2 = 15(-i)
x1x2 = -15i
x1x2 = 0-15i
Since
0 - 15i = a+ bi
Compare
a = 0
-15- = bi
b = -15
Hence a = 0, b = -15
