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Two blocks connected by a cord passing over a small, frictionless pulley rest on frictionless planes (the figure ).

A-Which way will the system move?

B-What is the acceleration of the blocks?

C-What is the tension in the cord?

Two blocks connected by a cord passing over a small frictionless pulley rest on frictionless planes the figure AWhich way will the system move BWhat is the acce class=

Respuesta :

let suppose that the system will move to the left 
so, to happen this50kg body along the slope :
T - m1gsin53 = m1a
100kg body along the slope :
m2gsin30 - T = m2a

adding both of the equations
m2gsin30 - m1gsin53 = a(m1+m2)
g(m2sin30-m1sin53) / (m1+m2) = a
a = 0.671
System will go to left as a is positive.
Which also gives you the answer for b.

Part A: The acceleration in the considered direction is positive. It means that the system will move on the left side.

Part B: The acceleration of the system is 0.65 m/s2.

Part C: The tension on the string is 424.5 N.

What is acceleration?

Acceleration is defined as the rate at which velocity changes with time, in terms of both speed and direction.

Given that two blocks connected by a cord passing over a small, frictionless pulley rest on the frictionless plane as shown in the figure.

Let's consider that tension on the string is T and the acceleration of the system is a that will be in the left direction.

The net force on the left block is given as,

[tex]100 g sin 30^\circ - T = 100 \times a[/tex]

[tex]50g - T = 100 a[/tex]

[tex]50g - 100 a = T[/tex]

The net force on the right block is given as,

[tex]T - 50 g sin 53.1^\circ = 50 \times a[/tex]

[tex]T - 40g = 50 a[/tex]

[tex]T = 50 a + 40g[/tex]

When equating both the values of T, we get a,

[tex]50g - 100 a = 50a + 40g[/tex]

[tex]150 a= 10g[/tex]

[tex]a = \dfrac { 10\times 9.8}{150}[/tex]

[tex]a = 0.65\;\rm m/s^2[/tex]

Part A: The acceleration in the considered direction is positive. It means that the system will move on the left side.

Part B: The acceleration of the system is 0.65 m/s2.

Part C: The tension on the cord is given as,

[tex]T = 50 a + 40 g[/tex]

[tex]T = 50 \times 0.65 + 40 \times 9.8[/tex]

[tex]T = 424.5 \;\rm N[/tex]

Hence the tension on the string is 424.5 N.

To know more about the acceleration, follow the link given below.

https://brainly.com/question/2437624.

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