Question

Sophia cut a piece of wood that measured 10.2inches but she was supposed to cut 16 inches what is the percent error

Answer 1

Answer: 35.80 %

Step-by-step explanation:

Given

Sophia mistakenly cut 10.2 inches

The actual cut should be 16 inches

$\Rightarrow \% \text{error}=\dfrac{\text{Actual dimension-Faulty dimension}}{\text{Actual dimension}}\times 100\\\\\Rightarrow \% \text{error}=\dfrac{16-10.2}{16.2}\times 100=35.80\%$