A building is being knocked down with a wrecking ball, which is a big metal sphere that swings on a 12-m-long cable. You are (unwisely!) standing directly beneath the point from which the wrecking ball is hung when you notice that the ball has just been released and is swinging directly toward you. How much time do you have to move out of the way?

Respuesta :

Answer:

Time to move out of the way = 1.74 s

Explanation:

This case is similar to simple pendulum. The period of simple pendulum is given by [tex]2\pi \sqrt{\frac{l}{g} }[/tex].

 Period of wrecking ball [tex]=2\pi \sqrt{\frac{l}{g}}=2\pi \sqrt{\frac{12}{9.81}}=6.95s[/tex]

 Time to move out of the way is one fourth of period = 6.95/4 = 1.74 seconds.

 Time to move out of the way = 1.74 s

The type of motion executed will be the simple harmonic motion. The time do you have to move out of the way will be 1.74 sec.

What is simple harmonic motion?

When an object executes a to and fro motion in the definite plane when it is tied with the string. The type of motion will be the simple harmonic motion.

Simple harmonic motion is a form of periodic motion in mechanics and physics in which the restoring force on the moving item is directly proportional to the size of the object.

The time period is given by the formula;

[tex]\rm t= 2\pi \sqrt{\frac{l}{g} } \\\\ \rm t= 2\times 3.14 \sqrt{\frac{12}{9.81} } \\\\ \rm t=1.74 \sec[/tex]

Hence the time do you have to move out of the way will be 1.74 sec.

To learn more about the simple harmonic motion refer to the link;

https://brainly.com/question/17315536