Question

The coefficients of friction between a block of mass 0.5 kg and a surface are μs = 0.75 and μk = 0.45. Assume the only other force acting on the block is that due to gravity. What is the magnitude of the frictional force (in newtons) on the block if the block is at rest and the surface is horizontal? Use g = 9.79 m/s2

Answer 1

The maximum frictional force will be .75(mg), but since no other forces are acting on the block, the actual frictional force has 0 magnitude. Seems like kinda a trick question.

Answer 2

The magnitude of the frictional force (in newtons) on the block if the block is at rest and the surface is horizontal is 3.67N.

What is frictional force?

When an object is moving on a rough surface, it experiences opposition. This opposing force is called the friction force.

Given is the coefficients of friction between a block of mass 0.5 kg and a surface are μs = 0.75 and μk = 0.45. Assume the only other force acting on the block is that due to gravity.

The friction force is given by

f = coefficient of friction x Normal force

The block is at rest and the surface is horizontal when gravitational acceleration is g = 9.79 m/s²

f =μs N =μs mg

f = 0.75 x  0.5 x 9.79

f = 3.67 N

Thus, the friction force is 3.67 N.

Learn more about friction force.

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