Question

A spinner is divided into 20 equal sections. what is the probability of the spinner's pointer landing on section 5?

Answer 1

1/20 would be the correct answer

Answer 2

Answer: $\dfrac{1}{20}$

Step-by-step explanation:

Given : The number of equal sections : 20

Then the probability of the spinner's pointer landing on each section will be :-

$\dfrac{\text{One}}{\text{Total sections}}\\\\=\dfrac{1}{20}$

Since , the probability of landing the spinner's pointer at any section is equal.

Therefore, the probability of the spinner's pointer landing on section 5$=\dfrac{1}{20}$